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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2018 · Mains Paper II

Q1(m). Anthracene photodimerization

Question

Anthracene in benzene undergoes 2C₁₄H₁₀+hν→C₂₈H₂₀. What quantum yield is expected ideally? Explain an observed value of 0.5.

Answer in brief

Ideally one absorbed photon produces one dimer and consumes two anthracene molecules: Φ_(dimer)=1 or Φ_(disappearance)=2, depending on the stated convention.

Key points

  • Absorption gives A*; a productive encounter with ground-state anthracene forms the dimer: A+hν→ A*, then A*+A→ A₂.
  • Not every excited molecule reaches a productive encounter. Fluorescence, internal conversion, intersystem crossing and quenching compete with dimer formation, reducing the chemical yield.
  • If 0.5 denotes anthracene disappearance per photon, the productive fraction is 0.5/2=0.25.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(m), 2018 Mains Paper II: solution pages 5 and 6
Solution pages 5 and 6 of 17

CoversAnthracene photodimerizationPhotochemistry