UPSC Combined Geo-Scientist, Mains · 2020 · Mains Paper II
Q1(m). Hydrogen rotational spectra
Question
Why is rigid H₂ inactive in ordinary rotational spectroscopy but active in rotational Raman spectroscopy?
Answer in brief
H₂ has no permanent electric dipole but has anisotropic polarisability.
Key points
- Electric-dipole microwave rotational absorption requires a permanent molecular dipole. Homonuclear H₂ has none, so ordinary electric-dipole pure rotational transitions are forbidden.
- Raman scattering couples through the induced dipole, μ_(ind)=α E. The polarisability of hydrogen differs parallel and perpendicular to the bond, enabling rotational modulation.
- Rotational Raman transitions obey ΔJ=±2 (with ΔJ=0 for Rayleigh scattering). Nuclear-spin statistics affect line intensities, but do not remove the Raman activity.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

CoversHydrogen rotational spectraSpectroscopy
All parts of Question 1
- 1(a) Critical-point inflection5 marks
- 1(b) Boyle and inversion temperatures5 marks
- 1(c) Accuracy at high diffraction angle5 marks
- 1(d) Composition change and non-expansion work5 marks
- 1(e) Van't Hoff plots5 marks
- 1(f) Potassium sulfate activities5 marks
- 1(g) Reaction order and rate constant5 marks
- 1(h) Catalytic rate enhancement5 marks
- 1(i) Electrochemical potential of zinc ions5 marks
- 1(j) Open-circuit emf and equilibrium5 marks
- 1(k) Hermitian operators5 marks
- 1(l) Probabilities of quantum states5 marks
- 1(m) Hydrogen rotational spectra5 marks
- 1(n) Wavelength and the einstein5 marks
- 1(o) Uranyl-sensitised decomposition5 marks
- 1(p) HI photolysis yield5 marks