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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2022 · Mains Paper II

Q1(f). ΔG for compressing a real gas, from fugacities

Question

Calculate the Gibbs free energy change accompanying the compression of one mole of a gas at 25 °C from 20 to 200 atm. The fugacities of the gas be taken as 18 and 120 atm respectively at pressure of 20 and 200 atm.

Answer in brief

ΔG = RT ln(f₂/f₁) = +4.70 kJ mol⁻¹ (an ideal gas would need +5.71 kJ mol⁻¹).

Key points

  • At constant T, (∂G/∂P)T = Vm; for a real gas the fugacity replaces pressure: dG = RT d ln f.
  • Integrating: ΔG = RT ln(f₂/f₁).
  • ΔG = 8.314 × 298.15 × ln(120/18) = 2478.8 × 1.8971 = 4703 J mol⁻¹ = +4.70 kJ mol⁻¹.
  • Ideal gas: RT ln(200/20) = 5708 J mol⁻¹; the real gas needs less because the fugacity coefficient falls from 0.90 to 0.60 (attraction dominates).
  • ΔG > 0: compression is not spontaneous; work must be done on the gas.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(f), 2022 Mains Paper II: solution pages 7 and 8
Solution pages 7 and 8 of 37

CoversfugacityGibbs free energyreal gasfugacity coefficientcompression of a gas