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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2022 · Mains Paper II

Q1(n). Photon–molecule interaction in rotating HCl

Question

Citing the case of rotation of HCl molecule, explain how the photon–molecule interaction takes place. You may draw pictures or scheme to establish yourself.

Answer in brief

The rotating permanent dipole of HCl is an oscillating dipole; when its frequency matches that of the radiation, the field exerts a torque: a photon is absorbed and J → J + 1.

Key points

  • HCl has a permanent dipole moment, Hδ⁺–Clδ⁻, μ ≈ 1.1 D.
  • As it rotates, the dipole component along any fixed direction varies as μ cos ωt: the rotating dipole is an oscillating dipole.
  • At resonance (ν = rotational frequency) the field exerts a torque, energy is exchanged and the molecule absorbs (J → J + 1) or emits a photon.
  • Gross selection rule: μ ≠ 0 (H₂, N₂, CO₂ are inactive); specific rule ΔJ = ±1, as the photon carries one unit ℏ of angular momentum.
  • EJ = hcBJ(J + 1) ⇒ lines at ν̃ = 2B(J + 1); B = 10.44 cm⁻¹ gives lines at 20.9, 41.8, 62.6, 83.5 cm⁻¹ (far infrared).

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(n), 2022 Mains Paper II: solution pages 15 and 16
Solution pages 15 and 16 of 37

Coversrotational spectroscopyHClpermanent dipole momentselection rulesmicrowave spectrumrigid rotor