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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper I covers inorganic chemistry.

UPSC Combined Geo-Scientist, Mains · 2024 · Mains Paper I

Q1(b). Magnetic moment of titanium(III)

Question

The observed magnetic moment for K₃[TiF₆] is 1.70 μB. (i) Calculate μ (spin only) for this complex. (ii) Why is there a difference between calculated and observed values?

Answer in brief

Ti³⁺ is d¹, with one unpaired electron: μso = √3 = 1.73 μB. Spin–orbit coupling modifies the spin-only value.

Key points

  • Oxidation state: three K⁺ require [TiF₆]³⁻; x − 6 = −3, so x = +3.
  • Configuration: Ti³⁺ has one 3d electron. In an octahedral field it occupies t₂g: t₂g¹ eg⁰.
  • Spin-only formula: μso = √[n(n + 2)] μB = √[1(1 + 2)] μB = 1.73 μB.
  • The orbitally degenerate t₂g ground state permits residual orbital angular momentum and spin–orbit coupling.
  • For this less-than-half-filled d shell, coupling can lower the effective moment; 1.70 μB is close to the spin-only prediction.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(b), 2024 Mains Paper I: solution pages 3 and 4
Solution pages 3 and 4 of 33

Coversspin-only magnetic momentK3[TiF6]Ti3+ d1spin-orbit couplingorbital contribution