UPSC Combined Geo-Scientist, Mains · 2024 · Mains Paper I
Q1(b). Magnetic moment of titanium(III)
Question
The observed magnetic moment for K₃[TiF₆] is 1.70 μB. (i) Calculate μ (spin only) for this complex. (ii) Why is there a difference between calculated and observed values?
Answer in brief
Ti³⁺ is d¹, with one unpaired electron: μso = √3 = 1.73 μB. Spin–orbit coupling modifies the spin-only value.
Key points
- Oxidation state: three K⁺ require [TiF₆]³⁻; x − 6 = −3, so x = +3.
- Configuration: Ti³⁺ has one 3d electron. In an octahedral field it occupies t₂g: t₂g¹ eg⁰.
- Spin-only formula: μso = √[n(n + 2)] μB = √[1(1 + 2)] μB = 1.73 μB.
- The orbitally degenerate t₂g ground state permits residual orbital angular momentum and spin–orbit coupling.
- For this less-than-half-filled d shell, coupling can lower the effective moment; 1.70 μB is close to the spin-only prediction.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Topic notes: crystal field theory, with every Civil Services, IFoS and Geo-Scientist PYQ →
Coversspin-only magnetic momentK3[TiF6]Ti3+ d1spin-orbit couplingorbital contribution
All parts of Question 1
- 1(a) Minerals and their compositions5 marks
- 1(b) Magnetic moment of titanium(III)5 marks
- 1(c) Choosing indicators5 marks
- 1(d) Silica by volatilisation gravimetry5 marks
- 1(e) Spontaneity of Fe²⁺ oxidation5 marks
- 1(f) Oxidising power and charge transfer5 marks
- 1(g) pH dependence of cyanide masking5 marks
- 1(h) Terminal and bridging carbonyl bands5 marks
- 1(i) Identifying radioactive decay5 marks
- 1(j) Why ordinary lanthanoid carbonyls are unstable5 marks