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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper I covers inorganic chemistry.

UPSC Combined Geo-Scientist, Mains · 2024 · Mains Paper I

Q1(h). Terminal and bridging carbonyl bands

Question

The complex [Fe₂(Cp)₂(CO)₄] has one strong IR band at 1800 cm⁻¹ and other bands appeared at ~1980 cm⁻¹ and 2020 cm⁻¹ for CO. Account for each band with proper reason.

Answer in brief

The 1800 cm⁻¹ band is assigned to bridging CO; the ~1980 and 2020 cm⁻¹ bands are coupled terminal-CO stretching modes.

Key points

  • The low-frequency band indicates μ₂-CO bridges. A suitable form is Cp(CO)Fe(μ-CO)₂Fe(CO)Cp with an Fe–Fe bond.
  • Each terminal CO is bound to one Fe; each bridging CO is bonded through carbon to both metals.
  • Metal-to-CO π back-donation populates CO π* orbitals and lowers the C–O force constant. Bridging carbonyl stretches occur below terminal stretches.
  • The two terminal C–O oscillators give symmetry-adapted combinations and hence distinct stretching frequencies near 1980 and 2020 cm⁻¹.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(h), 2024 Mains Paper I: solution pages 9 and 10
Solution pages 9 and 10 of 33

Coversbridging carbonylterminal carbonylIR stretching frequency[CpFe(CO)2]2back-donation