UPSC Combined Geo-Scientist, Mains · 2024 · Mains Paper I
Q1(h). Terminal and bridging carbonyl bands
Question
The complex [Fe₂(Cp)₂(CO)₄] has one strong IR band at 1800 cm⁻¹ and other bands appeared at ~1980 cm⁻¹ and 2020 cm⁻¹ for CO. Account for each band with proper reason.
Answer in brief
The 1800 cm⁻¹ band is assigned to bridging CO; the ~1980 and 2020 cm⁻¹ bands are coupled terminal-CO stretching modes.
Key points
- The low-frequency band indicates μ₂-CO bridges. A suitable form is Cp(CO)Fe(μ-CO)₂Fe(CO)Cp with an Fe–Fe bond.
- Each terminal CO is bound to one Fe; each bridging CO is bonded through carbon to both metals.
- Metal-to-CO π back-donation populates CO π* orbitals and lowers the C–O force constant. Bridging carbonyl stretches occur below terminal stretches.
- The two terminal C–O oscillators give symmetry-adapted combinations and hence distinct stretching frequencies near 1980 and 2020 cm⁻¹.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Coversbridging carbonylterminal carbonylIR stretching frequency[CpFe(CO)2]2back-donation
All parts of Question 1
- 1(a) Minerals and their compositions5 marks
- 1(b) Magnetic moment of titanium(III)5 marks
- 1(c) Choosing indicators5 marks
- 1(d) Silica by volatilisation gravimetry5 marks
- 1(e) Spontaneity of Fe²⁺ oxidation5 marks
- 1(f) Oxidising power and charge transfer5 marks
- 1(g) pH dependence of cyanide masking5 marks
- 1(h) Terminal and bridging carbonyl bands5 marks
- 1(i) Identifying radioactive decay5 marks
- 1(j) Why ordinary lanthanoid carbonyls are unstable5 marks