UPSC Combined Geo-Scientist, Mains · 2024 · Mains Paper I
Q1(f). Oxidising power and charge transfer
Question
MnO₄⁻ is a stronger oxidizing agent than ReO₄⁻. Explain and relate the oxidizing abilities of these ions with the relative positions of their charge-transfer absorptions.
Answer in brief
MnO₄⁻ is reduced more readily and has lower-energy, longer-wavelength LMCT absorption than ReO₄⁻.
Key points
- Both metals are formally +7 and d⁰. Their intense bands arise from O-to-metal ligand-to-metal charge transfer, not d–d transitions.
- An O-based occupied orbital transfers an electron to a predominantly metal-based empty orbital, locally resembling reduction of the metal.
- The +7 state is more strongly stabilised for the heavier 5d metal Re, so reduction of Re(VII) is less favourable than of Mn(VII).
- The LMCT energy increases in the order MnO₄⁻ < TcO₄⁻ < ReO₄⁻; wavelengths follow the reverse order.
- Thus MnO₄⁻ absorbs in the visible and is intensely purple, whereas ReO₄⁻ absorbs at higher energy, chiefly in the ultraviolet.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Coverscharge transfer spectraLMCTpermanganate colourperrhenateoxidising power
All parts of Question 1
- 1(a) Minerals and their compositions5 marks
- 1(b) Magnetic moment of titanium(III)5 marks
- 1(c) Choosing indicators5 marks
- 1(d) Silica by volatilisation gravimetry5 marks
- 1(e) Spontaneity of Fe²⁺ oxidation5 marks
- 1(f) Oxidising power and charge transfer5 marks
- 1(g) pH dependence of cyanide masking5 marks
- 1(h) Terminal and bridging carbonyl bands5 marks
- 1(i) Identifying radioactive decay5 marks
- 1(j) Why ordinary lanthanoid carbonyls are unstable5 marks