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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2021 · Mains Paper II

Q1(b). Compressibility factor and Z against P plots

Question

Define compressibility factor (Z). Describe Z vs. P plots with a suitable example.

Answer in brief

Z = PVm/RT. Ideal gas: Z = 1. Real gases: Z < 1 where attraction dominates, Z > 1 where repulsion (molecular size) dominates; all curves start at Z = 1 as P → 0.

Key points

  • Compressibility factor: Z = PVm/RT = Vm(real)/Vm(ideal); a pure number, Z = 1 at all P and T for an ideal gas.
  • Initial slope (∂Z/∂P) at P → 0 = (b − a/RT)/RT: positive for H₂ (small a), negative for N₂, CH₄, CO₂ at 300 K.
  • At 300 K: H₂ rises at once; N₂ dips slightly (0.96); CH₄ to about 0.8; CO₂ (320 K) deepest (0.38 near 100 bar).
  • Depth of the minimum grows with a, i.e. with ease of liquefaction: CO₂ > CH₄ > N₂ > H₂.
  • At very high P every curve rises with nearly the same slope: repulsion (b) dominates.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(b), 2021 Mains Paper II: solution pages 3 and 4
Solution pages 3 and 4 of 36

Coverscompressibility factorZ vs P plotreal gasesvan der Waals constantsdeviation from ideal behaviour