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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2021 · Mains Paper II

Q1(i). Role of H₃PO₄ in the dichromate titration of Fe²⁺

Question

What is the role of phosphoric acid in the volumetric titration of Fe²⁺ ions and Cr₂O₇²⁻ ions when diphenylamine is used as internal indicator?

Answer in brief

H₃PO₄ complexes Fe³⁺ and lowers the Fe³⁺/Fe²⁺ potential, so diphenylamine (0.76 V) changes colour at 99.7 % titration, inside the steep jump; it also removes the yellow colour of Fe³⁺.

Key points

  • Diphenylamine is a redox indicator: colourless → violet at EIn ≈ 0.76 V.
  • Without H₃PO₄: E°′ ≈ 0.68 V (1 M H₂SO₄); E = 0.76 V is reached at 95.7 % titration: a premature end point.
  • H₃PO₄ forms stable, colourless phosphato complexes of Fe³⁺; the uncomplexed [Fe³⁺] falls, so E°′ falls to about 0.6 V or lower.
  • With 0.61 V, E = 0.76 V needs 99.7 % titration: the colour change falls inside the potential jump.
  • Second role: the yellow Fe³⁺ (chloro complexes) is decolourised, so the violet end point is seen clearly.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(i), 2021 Mains Paper II: solution pages 9 and 10
Solution pages 9 and 10 of 36

Coversdichromate titrationphosphoric aciddiphenylamine indicatorredox indicatorformal potentialferrous iron estimation