UPSC Combined Geo-Scientist, Mains · 2020 · Mains Paper III
Q1(g). Formation of excited calcium atoms
Question
Show how aqueous CaCl₂ produces excited neutral calcium atoms in a flame.
Answer in brief
Nebulisation, desolvation, vaporisation, dissociation and excitation occur in sequence.
Key points
- Nebulisation forms solution droplets. Solvent evaporation leaves fine salt particles, which vaporise and undergo gas-phase dissociation/chemical reactions.
- The desired analytical species is ground-state neutral Ca(g), not intact dissolved CaCl₂.
- Collisions transfer thermal energy: Ca(g)+E→Ca*(g). Radiative relaxation gives Ca*→Ca+hν.
- Oxide formation and ionisation Ca ⇌ Ca⁺ + e⁻ compete and can lower the neutral-atom population. Flame composition and an ionisation buffer may be important.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

CoversFormation of excited calcium atomsFlame atomisation
All parts of Question 1
- 1(a) Significant figures5 marks
- 1(b) Particle diameter in chromatography5 marks
- 1(c) NDIR determination of carbon monoxide5 marks
- 1(d) Thermobalance5 marks
- 1(e) Matrix effects in XRF5 marks
- 1(f) Sample introduction into ICP5 marks
- 1(g) Formation of excited calcium atoms5 marks
- 1(h) Spectrophotometric chromium in a mineral5 marks