Q1(a). Volume and critical temperature of two van der Waals gases
Gases A and B are van der Waals gases. Their van der Waals constants (in SI units) are: a = 21.764 (A) and 3.457 (B); 10³b = 0.024 (A) and 0.024 (B). (i) Which of these would occupy greater volume under identical conditions? (ii) Which gas has the highest critical temperature? [table of a and b values given in the paper]
Answer in brief
(i) B occupies the greater volume (smaller a, weaker attraction); (ii) A has the higher critical temperature: Tc ∝ a at equal b, ratio 6.30.
Key points
- Same b ⇒ same excluded volume (same molecular size); the gases differ only in a, the intermolecular attraction.
- aB < aA ⇒ smaller internal pressure a/Vm²; the molecules are pulled together less ⇒ B occupies the greater volume.
- Tc = 8a/27Rb; at equal b, Tc ∝ a: Tc(A)/Tc(B) = 21.764/3.457 = 6.30 ⇒ A has the higher Tc.
- Stronger attraction lets A be liquefied at a higher temperature.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Coversvan der Waals constantscritical temperatureTc = 8a/27Rbcompressibility factorreal gas volume
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