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UPSC Combined Geo-Scientist

Chemist

  • 2 objective papers
  • 120 questions each
  • 2 h per paper
  • 100 + 300 marks

Prelims Paper II covers chemistry.

UPSC Combined Geo-Scientist, Prelims · 2024 · Paper II, Chemistry

UPSC Geo-Scientist Prelims 2024 Chemistry (Paper II): answer key and solutions

All 120 questions of the 2024 Combined Geo-Scientist Prelims Paper II (chemistry), each with the answer and a short explanation in the hint-sheet style: the key fact first, numericals worked with units. Tap a number in the key to jump to the question; every question also has its own page.

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Answer key

Question paper: read or download the 2024 Paper II paper. Solutions are original work by VKC; question paper belongs to UPSC.

Q1Atomic structure / quantum numbers

Which among the following principal quantum numbers has/have five degenerate d-orbitals?

  1. (a) 2
  2. (b) 3 only
  3. (c) 4 only
  4. (d) Both 3 and 4

Answer: (d) Both 3 and 4

A d-subshell needs l = 2, which is allowed only when n ≥ 3 (l = 0 to n − 1). n = 2 has only 2s and 2p. Both n = 3 (3d) and n = 4 (4d) have five d-orbitals (m_l = −2 to +2), degenerate in a free atom. → (d)

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Q2Atomic structure / radial distribution

Which one of the following statements related to radial distribution plots for hydrogen atom is not correct?

  1. (a) Most probable radius varies as 3s > 3p > 3d.
  2. (b) Most probable radius varies as 1s < 2s < 3s.
  3. (c) Most probable radius varies as 2p < 3p.
  4. (d) Most probable radius varies as 3s < 3p < 3d.

Answer and explanation with the VKC plan

Q3Atomic structure / (n + l) rule

Which one of the following sets of quantum numbers represents the highest energy state?

  1. (a) n = 4, l = 0, m_l = 0, m_s = +½
  2. (b) n = 3, l = 0, m_l = 0, m_s = −½
  3. (c) n = 3, l = 1, m_l = 1, m_s = +½
  4. (d) n = 3, l = 2, m_l = 1, m_s = −½

Answer and explanation with the VKC plan

Q4Periodic table / metals and non-metals

Which one of the following groups of elements contains true metals only?

  1. (a) Carbon, boron, silicon
  2. (b) Magnesium, aluminium, selenium
  3. (c) Boron, carbon, nitrogen
  4. (d) Sodium, thallium, bismuth

Answer and explanation with the VKC plan

Q5f-block / lanthanides

The electronic configuration of an element A is [Xe]4f¹5d¹6s² and that of an element B is [Xe]4f³6s². The elements A and B are

  1. (a) transition element and lanthanide, respectively
  2. (b) lanthanide and actinide, respectively
  3. (c) transition element and actinide, respectively
  4. (d) both lanthanides

Answer and explanation with the VKC plan

Q6Periodic table / modern periodic law

The physical and chemical properties of elements are periodic functions of their

  1. (a) atomic weight
  2. (b) atomic size
  3. (c) atomic number
  4. (d) atomic shape

Answer and explanation with the VKC plan

Q7f-block / lanthanide contraction

Which one of the following represents the correct order of ionic radii among Y³⁺, La³⁺, Eu³⁺ and Lu³⁺?

  1. (a) Y³⁺ < La³⁺ < Eu³⁺ < Lu³⁺
  2. (b) Lu³⁺ < Eu³⁺ < La³⁺ < Y³⁺
  3. (c) Eu³⁺ < La³⁺ < Lu³⁺ < Y³⁺
  4. (d) Lu³⁺ < Y³⁺ < Eu³⁺ < La³⁺

Answer and explanation with the VKC plan

Q8Atomic structure / Slater's rules

Using Slater's rule, the effective nuclear charge experienced by 3d-electron in titanium (atomic number 22) is

  1. (a) 22·0
  2. (b) 7·53
  3. (c) 5·14
  4. (d) 3·65

Answer and explanation with the VKC plan

Q9p-block / catenation

Atomic size of nitrogen is less than carbon atom, yet carbon shows maximum catenation property while nitrogen does not. The reason for this is

  1. (a) lone pair-lone pair repulsions in N—N single bond make the bond weaker to allow catenation
  2. (b) catenation is not dependent on atomic size
  3. (c) carbon has poor multiple bonds formation ability
  4. (d) nitrogen exists as an inert gas and therefore does not react

Answer and explanation with the VKC plan

Q10Periodic properties / ionisation energy, electron affinity

Consider the following statements :

  1. Sulfur has a higher ionization energy than phosphorus.
  2. Sulfur has a lower ionization energy than phosphorus.
  3. Sulfur has a lower electron affinity than chlorine.

Which of the statements given above is/are correct?

  1. (a) 1 only
  2. (b) 2 only
  3. (c) 1 and 3
  4. (d) 2 and 3

Answer and explanation with the VKC plan

Q11Chemical bonding / bond angle (VSEPR)

Which one of the following represents the correct order of bond angle among H₂O, H₂Te, H₂Se and H₂S?

  1. (a) H₂O > H₂S > H₂Se > H₂Te
  2. (b) H₂S > H₂Se > H₂O > H₂Te
  3. (c) H₂O > H₂Se > H₂S > H₂Te
  4. (d) H₂Te > H₂O > H₂S > H₂Se

Answer and explanation with the VKC plan

Q12Periodic properties / metallic character, oxides

Consider the following statements :

  1. On moving from left to right in the periodic table, the metallic character of elements decreases.
  2. On moving from left to right in the periodic table, the oxides of elements become less basic.

Which of the statements given above is/are correct?

  1. (a) 1 only
  2. (b) 2 only
  3. (c) Both 1 and 2
  4. (d) Neither 1 nor 2

Answer and explanation with the VKC plan

Q13p-block / carbon allotropy

Carbon is able to show allotropic forms due to

  1. (a) its smaller size
  2. (b) its higher electronegativity
  3. (c) its higher ionization enthalpy and unavailability of d-orbitals
  4. (d) catenation and pπ—pπ bond formation

Answer and explanation with the VKC plan

Q14Atomic structure / electronic configuration

A neutral atom of an element has two K, eight L and five M electrons. What will be the total number of p-electrons in the element?

  1. (a) 9
  2. (b) 8
  3. (c) 7
  4. (d) 6

Answer and explanation with the VKC plan

Q15Ionic equilibrium / buffers, salt hydrolysis

Consider the following statements :

  1. Statement–1 : An aqueous solution of NaH₂PO₄ is acidic and that of Na₂HPO₄ is basic in nature.
  2. Statement–2 : An equimolar mixture of NaH₂PO₄ and Na₂HPO₄ acts as a buffer.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are true and Statement–1 is not the correct explanation of Statement–2
  2. (b) Both Statement–1 and Statement–2 are true and Statement–1 is the correct explanation of Statement–2
  3. (c) Statement–1 is true but Statement–2 is false
  4. (d) Statement–1 is false but Statement–2 is true

Answer and explanation with the VKC plan

Q16Chemical bonding / resonance, delocalisation

In SO₃, one p-orbital and two d-orbitals are used in S=O π-bond formation. However, all S=O bond lengths are identical. This is due to

  1. (a) involvement of equivalent hybrid orbitals in π-bonding
  2. (b) considerable polarity in bonds
  3. (c) delocalization of π-bonds in the molecule
  4. (d) ionic covalent resonance in the molecule

Answer and explanation with the VKC plan

Q17Chemical bonding / VSEPR, Lewis basicity

Consider the following statements regarding NF₃ :

  1. NF₃ has bond angle value much lower than tetrahedral bond angle.
  2. NF₃ is a good Lewis base.

Which of the statements given above is/are correct?

  1. (a) 1 only
  2. (b) 2 only
  3. (c) Both 1 and 2
  4. (d) Neither 1 nor 2

Answer and explanation with the VKC plan

Q18p-block / boron hydrides

Which one of the following reactions is not possible between diborane and ammonia?

  1. (a) B₂H₆ + NH₃ (Excess) —(Low T)→ B₂H₆·2NH₃
  2. (b) B₂H₆ + NH₃ (Excess) —(High T)→ (BN)ₓ
  3. (c) B₂H₆ + 2NH₃ —(RT, Aqueous medium)→ B₄H₁₀ + N₂ + 4H₂
  4. (d) B₂H₆ + 2NH₃ —(High T)→ B₃N₃H₆

Answer and explanation with the VKC plan

Q19Solid state / radius ratio, covalency

For ZnS, a radius ratio (r_{Zn²⁺}/r_{S²⁻}) of 0·52 suggests a coordination number, of 6 for both cation and anion. However, in reality, ZnS adopts a coordination number of 4 : 4. This is because

  1. (a) ZnS is a true covalent compound
  2. (b) ZnS is an ionic compound with considerable covalency
  3. (c) Zn²⁺ is too small to occupy octahedral holes
  4. (d) S²⁻ ions are too large to provide higher coordination number to Zn²⁺

Answer and explanation with the VKC plan

Q20Ionic solids / Born–Haber cycle

Theoretically calculated lattice energy (using Born-Landé equation) of hypothetical molecule NaCl₂ is –2180 kJ/mol while that of NaCl is –755 kJ/mol. (Both the molecules are assumed to be formed from elements in their standard states.) Yet NaCl is a stable molecule while NaCl₂ does not exist. The reason for this is

  1. (a) dissociation energy of Cl₂ molecule is too high
  2. (b) second ionization energy of Na metal is too high
  3. (c) electron affinity of Cl atom is too low
  4. (d) Born-Landé equation cannot predict the correct lattice energy of these molecules

Answer and explanation with the VKC plan

Q21Ionic solids / solubility

The solubility of an ionic compound in a solvent depends on

  1. (a) lattice enthalpy only
  2. (b) solvation enthalpy only
  3. (c) lattice enthalpy and solvation enthalpy both
  4. (d) ionization enthalpy of metal

Answer and explanation with the VKC plan

Q22Solid state / point defects

Consider the following statements regarding Frenkel defect in solids :

  1. Statement–1 : Compounds having Frenkel defects have some covalent character.
  2. Statement–2 : Compounds having Frenkel defects have small positive ions and large negative ions, where small positive ions are highly polarizing and large negative ions are readily polarized.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are true and Statement–2 is the correct explanation of Statement–1
  2. (b) Both Statement–1 and Statement–2 are true and Statement–2 is not the correct explanation of Statement–1
  3. (c) Statement–1 is true but Statement–2 is false
  4. (d) Statement–1 is false but Statement–2 is true

Answer and explanation with the VKC plan

Q23Main-group stereochemistry / Berry pseudorotation

Two types of F atoms in (CH₃)PF₄ are indistinguishable while in (CH₃)₂PF₃, equatorially placed F atom is distinguishable from apical F atom with the help of ¹⁹F NMR spectroscopy. The reason for the same is

  1. (a) (CH₃)PF₄ has a square pyramidal geometry while (CH₃)₂PF₃ has a trigonal bipyramidal geometry
  2. (b) (CH₃)PF₄ has all equivalent hybrid orbitals but (CH₃)₂PF₃ has non-equivalent hybrid orbitals
  3. (c) inductive effect of methyl groups is higher in (CH₃)₂PF₃ than in (CH₃)PF₄
  4. (d) two methyl groups pose higher rigidity in the molecule to allow pseudorotation in (CH₃)₂PF₃

Answer and explanation with the VKC plan

Q24Chemical bonding / Coulson's hybridisation

The bond angle in H₂O molecule is 104·5°. The p-character in non-bonding set of orbitals will be [where cos (104·5°) = −0·25]

  1. (a) 20%
  2. (b) 70%
  3. (c) 75%
  4. (d) 80%

Answer and explanation with the VKC plan

Q25Chemical bonding / valence bond theory

The wave function
\(\Psi = \Psi_{cov} + \lambda\Psi_{H^+H^-} + \lambda\Psi_{H^-H^+}\)
expresses the phenomenon of

  1. (a) vibration
  2. (b) resonance
  3. (c) conjugation
  4. (d) orbital

Answer and explanation with the VKC plan

Q26Coordination chemistry / Werner's theory

Werner confirmed the presence of primary and secondary valencies in the coordination compounds CoCl₃·6NH₃, CoCl₃·5NH₃ and CoCl₃·4NH₃ by

  1. (a) treating cold aqueous solutions of cobalt complexes with excess of silver nitrate solution
  2. (b) treating cold aqueous solutions of cobalt complexes with excess of barium nitrate solution
  3. (c) treating cold aqueous solutions of cobalt complexes with excess of barium chloride solution
  4. (d) treating cold aqueous solutions of cobalt complexes with excess of sodium nitrate solution

Answer and explanation with the VKC plan

Q27Coordination chemistry / chelate effect

Which one among the following chelate rings will be more stable?

  1. (a) Four-membered chelate ring
  2. (b) Five-membered chelate ring
  3. (c) Six-membered chelate ring
  4. (d) Seven-membered chelate ring

Answer and explanation with the VKC plan

Q28Coordination chemistry / IUPAC nomenclature

Which one of the following is the correct IUPAC name of Li[AlH₄]?

  1. (a) Lithium aluminium hydride
  2. (b) Lithium aluminium tetrahydride
  3. (c) Lithium tetrahydridoaluminate(III)
  4. (d) Lithium tetrahydroaluminate(III)

Answer and explanation with the VKC plan

Q29Coordination chemistry / geometrical isomerism

Consider the following reaction :
[Co(NH₃)₄Cl₂]⁺ + Cl⁻ → [Co(NH₃)₃Cl₃] + NH₃

How many isomers of the product complex are possible for the above reaction?

  1. (a) 1
  2. (b) 2
  3. (c) 3
  4. (d) 5

Answer and explanation with the VKC plan

Q31Coordination chemistry / formula from name

The formula for the coordination compound amminediaquachlorido-platinum(IV) tetrachloridoplatinate(II) is

  1. (a) [PtCl(NH₃)(H₂O)₂][PtCl₄]
  2. (b) [PtCl(NH₃)(H₂O)₂]₂[PtCl₄]₃
  3. (c) [PtCl(NH₃)(H₂O)₂]₃[PtCl₄]₂
  4. (d) [PtCl(NH₃)(H₂O)₂]₂[PtCl₄]

Answer and explanation with the VKC plan

Q33p-block / acidic oxides

Which one of the following represents the correct order of acidity among CO₂, SO₂ and SO₃?

  1. (a) SO₃ > SO₂ > CO₂
  2. (b) SO₂ > SO₃ > CO₂
  3. (c) SO₂ > CO₂ > SO₃
  4. (d) CO₂ > SO₂ > SO₃

Answer and explanation with the VKC plan

Q34Ionic equilibrium / Ostwald's dilution law

Which of the following statements regarding Ostwald's dilution law is/are not correct? (Where α = degree of dissociation, k = equilibrium constant for dissociation, c = concentration of solution)

  1. Activity coefficients are taken as unity.
  2. Ostwald's law is valid for strong electrolytes.
  3. One may conclude \(\alpha = \sqrt{\frac{k}{c}}\).

Select the correct answer using the code given below.

  1. (a) 1 only
  2. (b) 2 only
  3. (c) 1 and 3
  4. (d) 2 and 3

Answer and explanation with the VKC plan

Q35Ionic equilibrium / ionic product of water

Which one of the following statements is correct?

  1. (a) Water is strong electrolyte.
  2. (b) The value of ionic product of water varies with temperature.
  3. (c) The concentrations of H⁺ and OH⁻ in 10⁻⁵ M HCl solution are same.
  4. (d) The ionization constant and ionic product of water are same.

Answer and explanation with the VKC plan

Q36Ionic equilibrium / Henderson equation

The pH of a buffer solution containing 6·0 mL of CH₃COOH (0·2 M) and 4·0 mL of CH₃COONa (0·2 M) solutions will be approximately [where pK_a (CH₃COOH) = 4·76; log 2 = 0·30, log 3 = 0·48]

  1. (a) 6·0
  2. (b) 5·13
  3. (c) 4·58
  4. (d) 2·46

Answer and explanation with the VKC plan

Q37Ionic equilibrium / salt hydrolysis

Which one of the following does not represent a correct expression for hydrolysis constant for the equilibrium reaction A⁻ + H₂O ⇌ OH⁻ + HA ?

  1. (a) K_h = [OH⁻][HA]/[A⁻]
  2. (b) pK_h = pK_w − pK_a
  3. (c) K_h = K_w/K_a
  4. (d) K_h = [OH⁻][HA]

Answer and explanation with the VKC plan

Q38Analytical chemistry / primary standards

Which one among the following compounds does not form primary standard solution?

  1. (a) Na₂CO₃
  2. (b) NaOH
  3. (c) ZnO
  4. (d) Potassium hydrogen phthalate

Answer and explanation with the VKC plan

Q39Analytical chemistry / redox titration

While performing the titration of KMnO₄ with clear Mohr's salt solution, a student obtained brown precipitate in the conical flask instead of a colourless solution, much before the end point was reached. What could be the possible source of error?

  1. (a) Reaction mixture was not heated to 60 °C
  2. (b) Fe²⁺ in the Mohr's salt solution hydrolyzed to precipitate brown hydroxide
  3. (c) Reaction medium was not made acidic
  4. (d) Too large quantity of KMnO₄ had been added to the Mohr's salt solution

Answer and explanation with the VKC plan

Q40Analytical chemistry / complexometry

In which one of the following titrations are metal-ion indicators used?

  1. (a) Acid-base titration
  2. (b) Precipitation titration
  3. (c) Complexometric titration
  4. (d) Redox titration

Answer and explanation with the VKC plan

Q41Gaseous state / kinetic theory

The total kinetic energy of 2 moles of an ideal gas at 300 K is approximately (where R = 8·3 JK⁻¹ mol⁻¹)

  1. (a) 1·25 × 10⁻²⁰ J
  2. (b) 6·3 × 10⁻²¹ J
  3. (c) 7·5 × 10³ J
  4. (d) 1·9 × 10³ J

Answer and explanation with the VKC plan

Q42Gaseous state / kinetic theory

The root mean square velocity of one mole of a monatomic gas having molar mass M is u_rms. The relation between u_rms and the average kinetic energy E of the gas is

  1. (a) \(u_{rms} = \sqrt{\frac{E}{3M}}\)
  2. (b) \(u_{rms} = \sqrt{\frac{2E}{M}}\)
  3. (c) \(u_{rms} = \sqrt{\frac{E}{2M}}\)
  4. (d) \(u_{rms} = \sqrt{\frac{3E}{2M}}\)

Answer and explanation with the VKC plan

Q43Gaseous state / kinetic theory

Consider the following statements regarding kinetic energy of a gas :

  1. Statement–1 : At 25 °C, the average kinetic energy of hydrogen gas molecules is the same as that of helium gas atoms.
  2. Statement–2 : The kinetic energy of a gas depends on the temperature and does not depend on the nature of the gas.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are true and Statement–2 is the correct explanation of Statement–1
  2. (b) Both Statement–1 and Statement–2 are true and Statement–2 is not the correct explanation of Statement–1
  3. (c) Statement–1 is true but Statement–2 is false
  4. (d) Statement–1 is false but Statement–2 is true

Answer and explanation with the VKC plan

Q44Gaseous state / van der Waals constants

Consider the following van der Waals' constant values of two gases X and Y :

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q44: figure printed with the question

Which one of the following is correct with respect to the van der Waals' constant values of X and Y in the table given above?

  1. (a) X is more easily liquefied than Y
  2. (b) Y is more easily liquefied than X
  3. (c) Ease of liquefaction does not depend upon the van der Waals' constant a
  4. (d) Ease of liquefaction does not depend upon the van der Waals' constant b

Answer and explanation with the VKC plan

Q45Gaseous state / Maxwell distribution

Consider the following statements regarding speed distribution of molecules :

  1. The total area under the plots of \(\left(\frac{1}{N}\right)\left(\frac{dN_u}{du}\right)\) versus u is a measure of the total number of molecules in the collection.
  2. The curve at any temperature is parabolic near the origin.
  3. The majority of molecules have speeds which cluster around the average value ū in the distribution curve.

Which of the statements given above is/are correct?

  1. (a) 1 and 2
  2. (b) 1 and 3
  3. (c) 2 and 3
  4. (d) 3 only

Answer and explanation with the VKC plan

Q46Gaseous state / mean free path

At constant volume, the mean free path of a gas is

  1. (a) directly proportional to temperature only
  2. (b) inversely proportional to pressure
  3. (c) directly proportional to both temperature and pressure
  4. (d) independent of temperature and pressure

Answer and explanation with the VKC plan

Q47Gaseous state / Graham's law

Hydrogen molecule (H₂) with molar mass 2 g mol⁻¹ effuses through a small hole at a temperature of 300 K and pressure of 5 torr. Under the same conditions, methane (CH₄) with molar mass 16 g mol⁻¹ is also allowed to effuse. The ratio of the rate of effusion of hydrogen (r_{H₂}) and methane (r_{CH₄}) is

  1. (a) 2·828 : 1
  2. (b) 1 : 2·828
  3. (c) 1 : 8
  4. (d) 8 : 1

Answer and explanation with the VKC plan

Q48Thermodynamics / adiabatic work

The work involved in a reversible adiabatic expansion of an ideal gas from p_i and V_i to p_f and V_f is given by

  1. \(w = \frac{p_f V_f - p_i V_i}{\gamma - 1}\)
  2. \(w = -nC_{v,m}T_i\left[1-\left(\frac{p_f}{p_i}\right)^{\frac{R}{C_{p,m}}}\right]\)
  3. \(w = \frac{p_f V_f - p_i V_i}{1-\gamma}\)
  4. \(w = nC_{p,m}T_i\left[1-\left(\frac{p_f}{p_i}\right)^{\frac{R}{C_{p,m}}}\right]\)

Select the correct answer using the code given below.

  1. (a) 1 and 2 only
  2. (b) 1, 2 and 3 only
  3. (c) 3 and 4 only
  4. (d) 1, 2, 3 and 4

Answer and explanation with the VKC plan

Q49Thermodynamics / intensive and extensive properties

Consider the following variables :

  1. Dielectric constant
  2. Surface tension
  3. Energy
  4. Enthalpy

Which one of the following regarding classification of variables is correct?

  1. (a) 1 and 3 are intensive variables; 2 and 4 are extensive variables
  2. (b) 1 and 2 are intensive variables; 3 and 4 are extensive variables
  3. (c) 1 and 4 are intensive variables; 2 and 3 are extensive variables
  4. (d) 2 and 3 are intensive variables; 1 and 4 are extensive variables

Answer and explanation with the VKC plan

Q50Thermodynamics / state functions

Consider the following statements regarding compressibility factor (Z) :

  1. Statement–1 : If a system at state A is converted to state B by two methods (reversible compression and irreversible compression), then the change in internal energy of the system is the same in both the processes.
  2. Statement–2 : Change in internal energy is a state function.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are true and Statement–2 is the correct explanation of Statement–1
  2. (b) Both Statement–1 and Statement–2 are true and Statement–2 is not the correct explanation of Statement–1
  3. (c) Statement–1 is true but Statement–2 is false
  4. (d) Statement–1 is false but Statement–2 is true

Answer and explanation with the VKC plan

Q51Thermodynamics / internal energy

A 0·04 mole sample of a monatomic gas at 1·00 atm pressure and 298 K expands isothermally and reversibly from an initial volume of 1·0 L to 10·0 L. It is then heated to 500 K, followed by isothermal compression to 1·00 L and finally cooled to 25 °C. The ΔU for the overall process is

  1. (a) 228 J
  2. (b) −228 J
  3. (c) zero
  4. (d) 456 J

Answer and explanation with the VKC plan

Q52Thermodynamics / Joule–Thomson effect

Consider the following statements :

  1. Statement–1 : The temperature of a perfect gas is unchanged by Joule-Thomson expansion.
  2. Statement–2 : For a perfect gas, Joule-Thomson coefficient (μ) is zero.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are true and Statement–2 is the correct explanation of Statement–1
  2. (b) Both Statement–1 and Statement–2 are true and Statement–2 is not the correct explanation of Statement–1
  3. (c) Statement–1 is true but Statement–2 is false
  4. (d) Statement–1 is false but Statement–2 is true

Answer and explanation with the VKC plan

Q53Thermodynamics / free expansion

In a free expansion process

  1. (a) the work done is zero and the heat transfer is zero
  2. (b) the work done is zero but the heat flows into the system
  3. (c) work is done by the system but the heat transfer is zero
  4. (d) work is done on the system and the heat flows out of the system

Answer and explanation with the VKC plan

Q54Thermochemistry / Hess's law

Consider the following hypothetical reactions :
X (g) + Y (g) → XY (g); ΔH₁ = a kJ mol⁻¹
X (g) + Z (g) → XZ (g); ΔH₂ = b kJ mol⁻¹
ΔH for the reaction
Y (g) + XZ (g) → XY (g) + Z (g)
will be

  1. (a) (a + b) kJ mol⁻¹
  2. (b) a kJ mol⁻¹
  3. (c) b kJ mol⁻¹
  4. (d) (a − b) kJ mol⁻¹

Answer and explanation with the VKC plan

Q56Thermodynamics / Gibbs energy

Consider the following reaction :
H₂ (g) + ½O₂ (g) → H₂O (l)
The values of ΔH and ΔG are −290 kJ and −230 kJ, respectively, at 300 K. What will be the value of ΔG at 320 K, assuming that there is no variation of ΔH and ΔS with temperature?

  1. (a) 0·2 kJ
  2. (b) −532 kJ
  3. (c) −226 kJ
  4. (d) −49 kJ

Answer and explanation with the VKC plan

Q57Thermodynamics / spontaneity

Consider the following statements regarding change of enthalpy (ΔH) and change of entropy (ΔS) for a chemical reaction at any temperature T :

  1. If ΔH is negative and ΔS is positive, the reaction will be spontaneous at all temperatures.
  2. If ΔH is positive and ΔS is negative, the reaction will be spontaneous at low temperatures.
  3. When both ΔH and ΔS are positive, the reaction will proceed spontaneously at high temperatures.

Which of the statements given above is/are correct?

  1. (a) 1 and 2
  2. (b) 1 and 3
  3. (c) 2 and 3
  4. (d) 2 only

Answer and explanation with the VKC plan

Q58Thermodynamics / spontaneity

Consider the following reactions :

  1. H₂ (g) + ½O₂ (g) → H₂O (l); Δ_rH = −285·8 kJ mol⁻¹
  2. ½N₂ (g) + O₂ (g) → NO₂ (g); Δ_rH = +33·2 kJ mol⁻¹

Which one of the following is correct with respect to the above reactions?

  1. (a) Reaction 1 is endothermic and non-spontaneous at all temperatures
  2. (b) Reaction 2 is exothermic and spontaneous at all temperatures
  3. (c) Reaction 2 is endothermic and non-spontaneous at all temperatures
  4. (d) Reaction 1 is exothermic and spontaneous at all temperatures

Answer and explanation with the VKC plan

Q59Solutions / abnormal colligative properties

The experimental results of colligative properties of solutions are often found to differ from the calculated values due to

  1. association of the concerned solute
  2. dissociation of the concerned solute
  3. the solutions being often non-ideal

Select the correct answer using the code given below.

  1. (a) 1 and 2 only
  2. (b) 2 and 3 only
  3. (c) 1 and 3 only
  4. (d) 1, 2 and 3

Answer and explanation with the VKC plan

Q60Solutions / relative lowering of vapour pressure

The vapour pressure of pure water decreases from 24 torr to 23 torr on adding x amount of a solute (molar mass 480 g mol⁻¹) in 150 g of water. The value of x is

  1. (a) 114 g
  2. (b) 128 g
  3. (c) 167 g
  4. (d) 1124 g

Answer and explanation with the VKC plan

Q61Solutions / osmotic pressure

Consider a solution of 50 g of an enzyme dissolved in water to give 2 dm³ of solution at 27 °C. The osmotic pressure of the given solution is (where molar mass of enzyme = 90000 g mol⁻¹ and R = 0·083 dm³ bar K⁻¹ mol⁻¹)

  1. (a) 0·49 kPa
  2. (b) 0·69 kPa
  3. (c) 0·89 kPa
  4. (d) 1·09 kPa

Answer and explanation with the VKC plan

Q62Solutions / elevation of boiling point

Consider the following values of normal boiling point and molal boiling point elevation constant for some solvents :

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q62: figure printed with the question

Which one of the following solutions would result in the greatest boiling point elevation?

  1. (a) 0·05 M lithium chloride in water
  2. (b) 0·05 M lithium chloride in ethanol
  3. (c) 0·05 M magnesium chloride in water
  4. (d) 0·05 M magnesium chloride in ethanol

Answer and explanation with the VKC plan

Q63Solutions / depression of freezing point

When a non-volatile solute is dissolved in a volatile solvent, the depression in the freezing point is

  1. (a) inversely proportional to the molality of the solution
  2. (b) directly proportional to the molality of the solution
  3. (c) independent of the amount of solute present in the solution
  4. (d) directly proportional to the mole fraction of the solvent present

Answer and explanation with the VKC plan

Q64Solutions / Henry's law

Consider the following statements regarding Henry's law :

  1. The Henry's law constant depends on the nature of the gas.
  2. CO₂ is more soluble than O₂.
  3. The Henry's law constant does not depend on the nature of the solvent.
  4. The Henry's law constant depends on the temperature.

(The Henry's law constant values of CO₂ and O₂ in water at 298 K are 3·01 × 10³ kPa kg mol⁻¹ and 7·92 × 10⁴ kPa kg mol⁻¹, respectively)
Which of the statements given above are correct?

  1. (a) 1 and 2 only
  2. (b) 1, 2 and 3
  3. (c) 1, 2 and 4
  4. (d) 3 and 4

Answer and explanation with the VKC plan

Q65Solutions / Henry's law

The value of the Henry's law constant of O₂ in water at 298 K is 8·0 × 10⁴ kPa kg mol⁻¹. When its partial pressure is 20 kPa, the molar concentration of O₂ in water at 25 °C is

  1. (a) 25 mmol dm⁻³
  2. (b) 0·25 mmol dm⁻³
  3. (c) 0·4 × 10⁻³ kg mol⁻¹
  4. (d) 4 × 10⁻³ mol kg⁻¹

Answer and explanation with the VKC plan

Q66Electrochemistry / molar conductivity

A conductivity cell was calibrated using 0·1 M KCl solution and the measured resistance was 100 Ω. The resistance of the same cell when filled with 0·02 M KCl solution is 500 Ω. The molar conductivity of 0·02 M KCl solution will be (the conductivity of 0·1 M KCl solution is 1·3 S m⁻¹)

  1. (a) 13·0 S cm² mol⁻¹
  2. (b) 130·0 × 10⁻⁴ S cm² mol⁻¹
  3. (c) 130·0 S cm² mol⁻¹
  4. (d) 260·0 S cm² mol⁻¹

Answer and explanation with the VKC plan

Q67Electrochemistry / Kohlrausch's law

The molar conductivities at infinite dilution Λ°_m for HNO₃, CH₃COOH and NaNO₃ are 421·2 S cm² mol⁻¹, 391·0 S cm² mol⁻¹ and 121·5 S cm² mol⁻¹, respectively. The Λ°_m for CH₃COONa will be

  1. (a) 51·5 S cm² mol⁻¹
  2. (b) 91·3 S cm² mol⁻¹
  3. (c) 151·5 S cm² mol⁻¹
  4. (d) 201·0 S cm² mol⁻¹

Answer and explanation with the VKC plan

Q68Electrochemistry / ionic mobility

The correct order of molar conductance at infinite dilution of LiCl, NaCl and KCl is

  1. (a) LiCl > NaCl > KCl
  2. (b) KCl > NaCl > LiCl
  3. (c) NaCl > KCl > LiCl
  4. (d) KCl > LiCl > NaCl

Answer and explanation with the VKC plan

Q69Electrochemistry / variation of conductivity with dilution

Consider the following statements regarding ionic molar conductivities :

  1. Statement–1 : With increasing dilution, the conductivity keeps on increasing.
  2. Statement–2 : With increasing dilution, the degree of ionization of weak electrolytes increases, and the mobility of ions also increases.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are true and Statement–2 is the correct explanation of Statement–1
  2. (b) Both Statement–1 and Statement–2 are true and Statement–2 is not the correct explanation of Statement–1
  3. (c) Statement–1 is true but Statement–2 is false
  4. (d) Statement–1 is false but Statement–2 is true

Answer and explanation with the VKC plan

Q70Electrochemistry / Walden's rule

Consider the following statements regarding ionic molar conductivities :

  1. Statement–1 : The Walden's rule holds good for tetramethylammonium ion and picrate ion.
  2. Statement–2 : The effective radii of tetramethylammonium ion and picrate ion in the solvent are larger and very different from the crystallographic radii of the ions.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are true and Statement–2 is the correct explanation of Statement–1
  2. (b) Both Statement–1 and Statement–2 are true and Statement–2 is not the correct explanation of Statement–1
  3. (c) Statement–1 is true but Statement–2 is false
  4. (d) Statement–1 is false but Statement–2 is true

Answer and explanation with the VKC plan

Q71Electrochemistry / ionic mobility, transport number

Consider the following statements regarding movement of ions :

  1. Ionic mobility is inversely proportional to the potential gradient.
  2. Ionic mobility is directly proportional to the ionic speed.
  3. Transport number of the ions is inversely proportional to the ionic speed.
  4. Sum of the transport numbers of ions in a solution is equal to one.

Which of the statements given above are correct?

  1. (a) 1 and 2 only
  2. (b) 1, 2 and 3
  3. (c) 3 and 4
  4. (d) 1, 2 and 4

Answer and explanation with the VKC plan

Q72Electrochemistry / Λ_m vs √c

The following graph shows the variation of molar conductance with the concentration of a/an

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q72: figure printed with the question
  1. (a) strong acid
  2. (b) weak acid
  3. (c) buffer
  4. (d) ethanol

Answer and explanation with the VKC plan

Q73Electrochemistry / Kohlrausch extrapolation

Consider the following graph showing the variation of molar conductance with concentration :

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q73: figure printed with the question

Which one of the following statements is correct with respect to the above graph?

  1. (a) Plot 1 can be extrapolated to obtain the molar conductance at infinite dilution of weak electrolytes.
  2. (b) Plot 1 can be extrapolated to obtain the molar conductance at infinite dilution of strong electrolytes.
  3. (c) Plot 2 can be extrapolated to obtain the molar conductance at infinite dilution of strong electrolytes.
  4. (d) Both plots 1 and 2 can be extrapolated to obtain the molar conductance at infinite dilution of strong and weak electrolytes, respectively.

Answer and explanation with the VKC plan

Q74Electrochemistry / Debye–Hückel–Onsager equation

The term A√c in the Onsager equation Λ = Λ^∞ − (A + BΛ^∞)√c represents the

  1. (a) decrease in molar conductivity due to the electrophoretic effect
  2. (b) decrease in molar conductivity due to the asymmetry effect
  3. (c) increase in molar conductivity due to the electrophoretic effect
  4. (d) increase in molar conductivity due to the asymmetry effect

Answer and explanation with the VKC plan

Q75Electrochemistry / Kohlrausch's law, Ostwald dilution

The conductivity of 0·001 M dichloroacetic acid solution is 3·88 × 10⁻⁵ S cm⁻¹. The molar conductivities at infinite dilution for HCl, NaCl and CHCl₂COONa (sodium dichloroacetate) are 426 S cm² mol⁻¹, 126 S cm² mol⁻¹ and 88 S cm² mol⁻¹, respectively. The degree of dissociation and dissociation constant of dichloroacetic acid will be respectively

  1. (a) 0·2 and 1·1 × 10⁻⁶
  2. (b) 0·1 and 1·1 × 10⁻⁶
  3. (c) 0·2 and 1·1 × 10⁻⁴
  4. (d) 0·1 and 1·1 × 10⁻⁵

Answer and explanation with the VKC plan

Q76Electrochemistry / solubility from conductance

The conductivity and molar conductance of CaF₂ at 18 °C are 4 × 10⁻⁵ S cm⁻¹ and 200 S cm² mol⁻¹, respectively. The K_sp for CaF₂ will be

  1. (a) 4·0 × 10⁻⁸
  2. (b) 3·2 × 10⁻¹¹
  3. (c) 8·0 × 10⁻¹²
  4. (d) 2·0 × 10⁻¹²

Answer and explanation with the VKC plan

Q77Electrochemistry / conductometric titration

In the given plot of conductometric titration of CH₃COOH vs. NaOH, the area around point (1) is curved due to

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q77: figure printed with the question
  1. (a) neutralization of weak acid with weak base
  2. (b) hydrolysis of the salt CH₃COONa
  3. (c) suppression of dissociation of CH₃COOH
  4. (d) poor conductance of CH₃COOH

Answer and explanation with the VKC plan

Q78Electrochemistry / anomalous transport numbers, complex ions

Consider the following table showing the apparent transport numbers of Cd²⁺ ion in CdI₂ solutions of different molalities :

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q78: figure printed with the question

Which one of the following interpretations is correct with respect to the table given above?

  1. (a) In dilute solutions, Cd²⁺ ion migrates towards the anode and I⁻ migrates towards the cathode and vice versa in concentrated solutions.
  2. (b) In dilute solutions, Cd²⁺ ion migrates towards the cathode and I⁻ migrates towards the anode and vice versa in concentrated solutions.
  3. (c) In dilute solutions, Cd²⁺ ion migrates towards the cathode and I⁻ migrates towards the anode and in concentrated solutions, Cd²⁺ ion migrates towards the cathode and CdI₄²⁻ migrates towards the anode.
  4. (d) In dilute solutions, Cd²⁺ ion migrates towards the anode and I⁻ migrates towards the cathode and in concentrated solutions, Cd²⁺ ion migrates towards the anode and CdI₄²⁻ migrates towards the cathode.

Answer and explanation with the VKC plan

Q79Electrochemistry / moving boundary method

The transport number of ions in a 1·0 M solution of AgNO₃ was determined using a 0·3 M solution of Cd(NO₃)₂ in the moving boundary method. When a current of 15 mA was passed for 30 min, the boundary swept through a volume of 0·1 cm³. The transport number of Ag⁺ is (Faraday's constant = 96500 C mol⁻¹)

  1. (a) 0·36
  2. (b) 0·64
  3. (c) 0·71
  4. (d) 0·83

Answer and explanation with the VKC plan

Q80Electrochemistry / moving boundary method

Which of the following electrolytes should be given to a chemist to be used as an indicator electrolyte in the determination of the transport number of Ag⁺ in AgNO₃ solution using the moving boundary method?

  1. (a) Cd(NO₃)₂
  2. (b) LiNO₃ only
  3. (c) CdCl₂ only
  4. (d) Both LiNO₃ and CdCl₂

Answer and explanation with the VKC plan

Q81Aromaticity / bond fixation in polycyclic arenes

Consider the following statements regarding structures of naphthalene and biphenylene :

  1. The C1-C2 bond order is more than C2-C3 bond in naphthalene.
  2. The C2-C3 bond order is more than C1-C2 bond in naphthalene.
  3. The C1-C2 bond order is more than C2-C3 bond in biphenylene.
  4. The C2-C3 bond order is more than C1-C2 bond in biphenylene.

Which of the statements given above are correct?

  1. (a) 1 and 3
  2. (b) 1 and 4
  3. (c) 2 and 3
  4. (d) 2 and 4

Answer and explanation with the VKC plan

Q82Organic / acidity of substituted benzoic acids

The correct order of increasing acid strength of the given carboxylic acids is

  1. (a) 4-acetylbenzoic acid < 4-cyanobenzoic acid < 4-hydroxybenzoic acid < benzene-1,4-dicarboxylic acid
  2. (b) 4-hydroxybenzoic acid < 4-acetylbenzoic acid < 4-cyanobenzoic acid < benzene-1,4-dicarboxylic acid
  3. (c) 4-hydroxybenzoic acid < benzene-1,4-dicarboxylic acid < 4-acetylbenzoic acid < 4-cyanobenzoic acid
  4. (d) 4-cyanobenzoic acid < 4-acetylbenzoic acid < benzene-1,4-dicarboxylic acid < 4-hydroxybenzoic acid

Answer and explanation with the VKC plan

Q83Heterocycles / basicity of azoles and azaindoles

The major products [X] and [Y] formed in the following reactions are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q83: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q83: answer options as printed
  1. (a) [X] = 1-methylbenzimidazolium protonated at N-1 (N bearing CH₃); [Y] = pyrrolo-pyridine protonated at the pyrrole N (NH₂⁺)
  2. (b) [X] = 1-methylbenzimidazolium protonated at N-3; [Y] = pyrrolo-pyridine protonated at the pyridine N (pyrrole NH intact)
  3. (c) [X] = 1-methylbenzimidazolium protonated at N-1 (N bearing CH₃); [Y] = pyrrolo-pyridine protonated at the pyridine N
  4. (d) [X] = 1-methylbenzimidazolium protonated at N-3; [Y] = pyrrolo-pyridine protonated at the pyrrole N (NH₂⁺)

Answer and explanation with the VKC plan

Q84Neighbouring group participation / α-amino effect, Bredt's rule

The correct decreasing order of reactivity towards ionization under acidic conditions of the following compounds is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q84: figure printed with the question
  1. (a) I > III > II
  2. (b) I > II > III
  3. (c) III > II > I
  4. (d) II > III > I

Answer and explanation with the VKC plan

Q85Aromaticity / annulene dianions (Hückel rule)

The products of which of the following reactions are aromatic in nature?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q85: figure printed with the question
  1. (a) I, II and IV only
  2. (b) II and III only
  3. (c) III and IV only
  4. (d) I, II, III and IV

Answer and explanation with the VKC plan

Q86Stereochemistry / R,S and relationships

Match the pair of compounds from Column–I with their stereochemical relationship with each other from Column–II and select the correct answer using the code given below the Columns :

Column–IColumn–II
(A) M and N1. Identical
(B) M and O2. Diastereomers
(C) M and P3. Enantiomers
(D) N and P
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q86: figure printed with the question
  1. (a) A-2, B-3, C-2, D-1
  2. (b) A-3, B-3, C-1, D-2
  3. (c) A-1, B-3, C-1, D-2
  4. (d) A-3, B-1, C-2, D-1

Answer and explanation with the VKC plan

Q87Stereochemistry / meso compounds

Which one of the following has an achiral stereoisomer?

  1. (a) 2,3-Dibromo-2,3-dimethylbutane
  2. (b) 2-Bromo-4-methylpentan-3-ol
  3. (c) 2,3-Dibromopentane
  4. (d) 1,2-Dibromocyclobutane

Answer and explanation with the VKC plan

Q88Stereochemistry / E,Z and R,S nomenclature

The structure which is consistent with (R, Z)-3,6-dimethyloct-3-ene as its IUPAC name is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q88: answer options as printed
  1. (a) skeletal structure (a): Z-alkene, C6 methyl on wedge
  2. (b) skeletal structure (b): E-alkene, C6 methyl on wedge
  3. (c) skeletal structure (c): Z-alkene, C6 methyl on wedge
  4. (d) skeletal structure (d): E-alkene, C6 methyl on hashed bond

Answer and explanation with the VKC plan

Q89Conformational analysis / steroids

Cholic acid, a major constituent of bile, has the structure as shown below. What are the positions of labeled I, II and III hydroxyl groups, respectively, in their chair conformations?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q89: figure printed with the question
  1. (a) Equatorial, equatorial and axial
  2. (b) Equatorial, equatorial and equatorial
  3. (c) Equatorial, axial and axial
  4. (d) Axial, axial and axial

Answer and explanation with the VKC plan

Q90Conformational analysis / gauche effect

In which one of the following compounds, the anti-conformer is more stable than gauche conformer?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q90: answer options as printed
  1. (a) HOCH₂CH₂OH
  2. (b) FCH₂CH₂F
  3. (c) BrCH₂CH₂Br
  4. (d) HOCH₂CH₂OMe

Answer and explanation with the VKC plan

Q91Reaction mechanism / SN1 and carbocation stability

The increasing order of SN1 solvolysis reactivity in ethanol of the following substrates is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q91: figure printed with the question
  1. (a) I < II < IV < III
  2. (b) III < I < IV < II
  3. (c) III < I < II < IV
  4. (d) II < III < IV < I

Answer and explanation with the VKC plan

Q92Neighbouring group participation / sulfur, ring expansion

The number of SN2 processes involved in the mechanism of the following reaction is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q92: figure printed with the question
  1. (a) two
  2. (b) three
  3. (c) four
  4. (d) five

Answer and explanation with the VKC plan

Q93Conformational analysis / selective tosylation, SN2 in decalins

The major products [X] and [Y] formed in the following reactions are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q93: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q93: answer options as printed
  1. (a) [X] = OTs on C-3 (less hindered OH), OH on C-2; [Y] = SPh (wedge) replaces the right-ring Br, left-ring Br retained
  2. (b) [X] = OTs on C-3 (less hindered OH), OH on C-2; [Y] = SPh (wedge) replaces the left-ring Br, right-ring Br retained
  3. (c) [X] = OTs on C-2 (next to the isopropyl carbon), OH on C-3; [Y] = SPh (wedge) replaces the right-ring Br, left-ring Br retained
  4. (d) [X] = OTs on C-2 (next to the isopropyl carbon), OH on C-3; [Y] = SPh (wedge) replaces the left-ring Br, right-ring Br retained

Answer and explanation with the VKC plan

Q94Organofluorine / nucleophilic vinylic substitution, SN2′

The major products [X] and [Y] formed in the following reactions are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q94: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q94: answer options as printed
  1. (a) [X] = F₃C(Ph)C=CF(OEt); [Y] = ClF₂C(Ph)C=CF(OEt)
  2. (b) [X] = F₂C=C(Ph)CF₂OEt; [Y] = ClF₂C(Ph)C=CF(OEt)
  3. (c) [X] = F₃C(Ph)C=CF(OEt); [Y] = F₂C=C(Ph)CF₂OEt
  4. (d) [X] = F₂C=C(Ph)CF₂OEt; [Y] = ClF₂C(Ph)C=C(F)OEt (OEt cis to Ph)

Answer and explanation with the VKC plan

Q95SN2 / ring size effects

The relative SN2 reactivity order of the following substrates is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q95: figure printed with the question
  1. (a) II < III < IV < I
  2. (b) II < III < I < IV
  3. (c) I < III < II < IV
  4. (d) IV < I < III < II

Answer and explanation with the VKC plan

Q96Thermodynamics of organic reactions / addition vs elimination

Which of the following statements are correct about the following reactions?

  1. Addition is favoured at low temperature whereas elimination is favoured at high temperature.
  2. Addition is favoured at high temperature whereas elimination is favoured at low temperature.
  3. At high temperature, ΔG is positive for addition reaction whereas ΔG is negative for elimination reaction.
  4. At high temperature, ΔG is negative for addition reaction whereas ΔG is positive for elimination reaction.
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q96: figure printed with the question

Select the correct answer using the code given below.

  1. (a) 1 and 3
  2. (b) 1 and 4
  3. (c) 2 and 3
  4. (d) 2 and 4

Answer and explanation with the VKC plan

Q97Stereochemistry / E2 and SN2 stereospecificity

The major products formed in E2 and SN2 reactions of the substrate [X] with sodium methoxide, respectively, are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q97: figure printed with the question
  1. (a) (Z)-3-methylhex-3-ene and (3R, 4R)-3-methoxy-4-methylhexane
  2. (b) (Z)-3-methylhex-3-ene and (3R, 4S)-3-methoxy-4-methylhexane
  3. (c) (E)-3-methylhex-3-ene and (3R, 4S)-3-methoxy-4-methylhexane
  4. (d) (E)-3-methylhex-3-ene and (3R, 4R)-3-methoxy-4-methylhexane

Answer and explanation with the VKC plan

Q98Elimination / stereochemistry of E2 and Ei

In which one of the following elimination reactions, deuterium is not retained in the alkene formed as the major product?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q98: answer options as printed
  1. (a) trans-decalyl bromide with adjacent D (cis to Br), NaOEt/EtOH
  2. (b) exo-2-norbornyl chloride with D at C-3, KOBuᵗ/t-BuOH
  3. (c) PhCH(OAc)–CHDPh acetate, heat
  4. (d) PhCHD–CH₂Br, KOEt/EtOH

Answer and explanation with the VKC plan

Q99Elimination / Hofmann vs Zaitsev

Which one of the following statements is correct regarding the given reaction?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q99: figure printed with the question
  1. (a) The major product formed is I and is called Zaitsev product.
  2. (b) The major product formed is I and is called Hofmann product.
  3. (c) The major product formed is II and is called Zaitsev product.
  4. (d) The major product formed is II and is called Hofmann product.

Answer and explanation with the VKC plan

Q100Amines / Hofmann exhaustive methylation

Which of the following substrates do not form trimethylamine as one of the products in its Hofmann exhaustive methylation method?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q100: figure printed with the question
  1. (a) I, II and III
  2. (b) I and II only
  3. (c) III, IV and V
  4. (d) IV and V only

Answer and explanation with the VKC plan

Q101Conformational analysis / E2 in trans-decalins

Which of the compounds in Pair A and Pair B are more reactive towards elimination reaction using NaOEt/EtOH?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q101: figure printed with the question
  1. (a) Pair A : I is more reactive than II
    Pair B : III is more reactive than IV
  2. (b) Pair A : I is more reactive than II
    Pair B : IV is more reactive than III
  3. (c) Pair A : II is more reactive than I
    Pair B : III is more reactive than IV
  4. (d) Pair A : II is more reactive than I
    Pair B : IV is more reactive than III

Answer and explanation with the VKC plan

Q102Elimination / stereospecific E2, E1cB

The major products [X] and [Y] formed in the following reactions are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q102: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q102: answer options as printed
  1. (a) [X] = (E)-3-methylhex-3-en-2-one; [Y] = (Z)-3-methylhex-3-en-2-one
  2. (b) [X] = [Y] = (Z)-3-methylhex-3-en-2-one
  3. (c) [X] = (Z)-3-methylhex-3-en-2-one; [Y] = (E)-3-methylhex-3-en-2-one
  4. (d) [X] = [Y] = (E)-3-methylhex-3-en-2-one

Answer and explanation with the VKC plan

Q103Alkenes / hydration methods

Match the reactions from Column–I with the major products formed from Column–II and select the correct answer using the code given below the Columns :

Column–IColumn–II
A. 3,3-dimethylbut-1-ene, i) Hg(OAc)₂, THF-H₂O; ii) NaBH₄1. 3,3-Dimethylbutan-1-ol
B. 3,3-dimethylbut-1-ene, i) B₂H₆, THF; ii) H₂O₂, NaOH2. 2,3-Dimethylbutan-2-ol
C. 3,3-dimethylbut-1-ene, H₂SO₄, H₂O3. 3,3-Dimethylbutan-2-ol
4. 2,3-Dimethylbutan-1-ol
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q103: figure printed with the question
  1. (a) A-2, B-4, C-1
  2. (b) A-4, B-3, C-2
  3. (c) A-3, B-1, C-2
  4. (d) A-3, B-4, C-1

Answer and explanation with the VKC plan

Q104Free-radical addition / peroxide (Kharasch) effect

Consider the following statements :

  1. Statement–1 : The peroxide effect is observed for the addition of HBr to alkene but not for the addition of HCl or HI.
  2. Statement–2 : Either of the two propagation steps for the addition of HCl or HI to alkene is endothermic in nature.

Which one of the following is correct with respect to the above statements?

  1. (a) Both Statement–1 and Statement–2 are correct and Statement–2 is the correct explanation of Statement–1
  2. (b) Both Statement–1 and Statement–2 are correct and Statement–2 is not the correct explanation of Statement–1
  3. (c) Statement–1 is correct but Statement–2 is incorrect
  4. (d) Statement–1 is incorrect but Statement–2 is correct

Answer and explanation with the VKC plan

Q105Oxidation / chemoselective epoxidation

The reagents [X] and [Y] required to carry out the following transformations are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q105: figure printed with the question
  1. (a) [X] = m-CPBA and [Y] = CH₃CO₃H
  2. (b) [X] = CH₃CO₃H and [Y] = m-CPBA
  3. (c) [X] = H₂O₂/NaOH and [Y] = CH₃CO₃H
  4. (d) [X] = CH₃CO₃H and [Y] = H₂O₂/NaOH

Answer and explanation with the VKC plan

Q106Carbonyl chemistry / double Michael addition

Which one of the following statements is not correct regarding the following reaction?
Dibenzalacetone + 1 mol Diethylmalonate —NaOEt→ Monocyclic product

  1. (a) The product is formed by two successive Michael additions.
  2. (b) The product is formed by Michael addition followed by intra-aldol condensation.
  3. (c) Monocyclic product does not give the test of unsaturation with bromine.
  4. (d) The double bond equivalence of monocyclic product is twelve.

Answer and explanation with the VKC plan

Q107Polymers / ionic chain polymerisation

Classify the following substituted styrenes with respect to their preferred mode of addition polymerization and select the correct answer accordingly :

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q107: figure printed with the question
  1. (a) I and IV undergo anionic polymerization while II and III undergo cationic polymerization
  2. (b) III and IV undergo cationic polymerization while I and II undergo anionic polymerization
  3. (c) I, III and IV undergo cationic polymerization while II undergoes anionic polymerization
  4. (d) I and IV undergo cationic polymerization while II and III undergo anionic polymerization

Answer and explanation with the VKC plan

Q108Stereochemistry / anti addition of bromine

Match the reactions from Column–I with the stereochemical outcome of the products described in Column–II and select the correct answer using the code given below the Columns :

Column–IColumn–II
A. (E)-cyclodecene + Br₂1. Formation of diastereomers
B. 1-methylcyclohexene + Br₂2. Formation of racemic mixture
C. cyclohexa-1,3-diene + Br₂3. Formation of meso-isomer
D. 3-methylcyclohexene (single enantiomer) + Br₂4. Formation of constitutional isomers
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q108: figure printed with the question
  1. (a) A-2, B-1, C-4, D-3
  2. (b) A-2, B-4, C-1, D-3
  3. (c) A-3, B-2, C-4, D-1
  4. (d) A-4, B-2, C-1, D-2

Answer and explanation with the VKC plan

Q109Aromatic substitution / aryne mechanism

Which one of the following statements is correct for the indicated reaction?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q109: figure printed with the question
  1. (a) The major product formed is I and the reaction proceeds through addition-elimination pathway.
  2. (b) The major product formed is II and the reaction proceeds through addition-elimination pathway.
  3. (c) The major product formed is I and the reaction proceeds through elimination-addition pathway.
  4. (d) The major product formed is II and the reaction proceeds through elimination-addition pathway.

Answer and explanation with the VKC plan

Q110Aromatic substitution / nitration then SNAr

The major product formed in the following reaction is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q110: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q110: answer options as printed
  1. (a) 4-chloro-2-nitroanisole (OMe and NO₂ ortho; Cl para to OMe)
  2. (b) 4-methoxy-3-nitrobenzotrifluoride (CF₃; NO₂ meta to CF₃; OMe para to CF₃)
  3. (c) 4-chloro-3-nitroanisole (OMe para to Cl; NO₂ ortho to Cl)
  4. (d) 4-methoxy-2-nitrobenzotrifluoride (NO₂ ortho to CF₃; OMe para to CF₃)

Answer and explanation with the VKC plan

Q111Aromatic substitution / aryne, tandem addition–cyclisation

The intermediate [X] and the major product [Y] formed in the following reaction are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q111: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q111: answer options as printed
  1. (a) [X] = aryl anion ortho to OMe, CH(Ph)CN meta to OMe; [Y] = 2-benzyl-3-cyano pattern (CH₂Ph ortho to OMe, CN next to CH₂OMe)
  2. (b) [X] = aryl anion ortho to OMe, CH(Ph)CN meta to OMe; [Y] = CN ortho to OMe, CH₂Ph next to CH₂OCH₃
  3. (c) [X] = CH(Ph)CN ortho to OMe, aryl anion meta to OMe; [Y] = CH₂Ph ortho to OMe, CN next to CH₂OMe
  4. (d) [X] = CH(Ph)CN ortho to OMe, aryl anion meta to OMe; [Y] = CN ortho to OMe, CH₂Ph next to CH₂OMe

Answer and explanation with the VKC plan

Q112Heterocycles / intramolecular Chichibabin amination

The major product formed in the following reaction is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q112: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q112: answer options as printed
  1. (a) tetrahydro-1,6-naphthyridine: NH ring fused at C-4/C-5 positions, aminopropyl at C-2
  2. (b) cyclopenta[b]pyridine bearing NH₂ on the five-membered ring, aminopropyl at C-2
  3. (c) 5,6,7,8-tetrahydro-1,8-naphthyridine (NH next to ring N), 3-aminopropyl at C-2
  4. (d) tetrahydro-1,5-naphthyridine (NH at β-position), 3-aminopropyl on the pyridine ring

Answer and explanation with the VKC plan

Q113Synthesis / Friedel–Crafts with blocking group

The correct sequence of reactions to accomplish the multi-step synthesis of 1-isobutyl-2-methylbenzene from benzene is
Benzene ⟶⟶ 1-Isobutyl-2-methylbenzene

  1. (a) [1] (CH₃)₂CHCOCl / AlCl₃; [2] HCl, Zn(Hg)/heat; [3] dilute H₂SO₄; [4] CH₃Cl, AlCl₃; [5] fuming H₂SO₄
  2. (b) [1] CH₃Cl, AlCl₃; [2] dilute H₂SO₄; [3] (CH₃)₂CHCOCl / AlCl₃; [4] HCl, Zn(Hg)/heat; [5] fuming H₂SO₄
  3. (c) [1] (CH₃)₂CHCl / AlCl₃; [2] fuming H₂SO₄; [3] CH₃Cl, AlCl₃; [4] dilute H₂SO₄
  4. (d) [1] (CH₃)₂CHCOCl / AlCl₃; [2] HCl, Zn(Hg)/heat; [3] fuming H₂SO₄; [4] CH₃Cl, AlCl₃; [5] dilute H₂SO₄

Answer and explanation with the VKC plan

Q114Aromatic substitution / directing effects

The major products [X] and [Y] formed in the following reactions are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q114: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q114: answer options as printed
  1. (a) [X] = Cl ortho to O on the 3,4-dimethylphenyl ring; [Y] = para-nitro benzalacetone
  2. (b) [X] = Cl ortho to O on the 3,4-dimethylphenyl ring; [Y] = meta-nitro benzalacetone
  3. (c) [X] = Cl para to O (between the two Me) on the 3,5-dimethylphenyl ring; [Y] = para-nitro benzalacetone
  4. (d) [X] = Cl para to O (between the two Me) on the 3,5-dimethylphenyl ring; [Y] = meta-nitro benzalacetone

Answer and explanation with the VKC plan

Q115Carbocation rearrangements / ring contraction

The major product formed in the following reaction is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q115: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q115: answer options as printed
  1. (a) hydrindane with 1-isopropylcyclopentene unit (ring-contracted, endocyclic C=C)
  2. (b) hydrindane with exocyclic isopropylidene on the five-membered ring (ring-contracted)
  3. (c) octalin with tetrasubstituted ring C=C bearing two methyls (methyl shift)
  4. (d) octalin with trisubstituted ring C=C and gem-methyl migrated (methyl shift)

Answer and explanation with the VKC plan

Q116Rearrangements / pinacol, migratory aptitude

The major products [X] and [Y] formed in the following reactions are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q116: figure printed with the question
UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q116: answer options as printed
  1. (a) [X] = (4-MeOC₆H₄)Ph₂C–CO–C₆H₄OMe-4; [Y] = (4-ClC₆H₄)Ph₂C–CO–C₆H₄Cl-4
  2. (b) [X] = (4-MeOC₆H₄)Ph₂C–CO–C₆H₄OMe-4; [Y] = (4-ClC₆H₄)₂PhC–COPh
  3. (c) [X] = (4-MeOC₆H₄)₂PhC–COPh; [Y] = (4-ClC₆H₄)Ph₂C–CO–C₆H₄Cl-4
  4. (d) [X] = (4-MeOC₆H₄)₂PhC–COPh; [Y] = (4-ClC₆H₄)₂PhC–COPh

Answer and explanation with the VKC plan

Q117Carbocations / hydride shift and Friedel–Crafts cyclisation

The reasonable carbocation intermediates which are likely to form in the reaction mechanism of the following transformation are

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q117: figure printed with the question
  1. (a) I, III and IV
  2. (b) III, IV and V
  3. (c) I, II and IV
  4. (d) II, III and V

Answer and explanation with the VKC plan

Q118Neighbouring group participation / ring size

Which substrate in each pair is expected to be faster in the indicated reaction?

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q118: figure printed with the question
  1. (a) I is more reactive than II whereas III is more reactive than IV
  2. (b) I is more reactive than II whereas IV is more reactive than III
  3. (c) II is more reactive than I whereas III is more reactive than IV
  4. (d) II is more reactive than I whereas IV is more reactive than III

Answer and explanation with the VKC plan

Q119SN1 / carbocation stabilisation

The relative rate of solvolysis in aqueous acetone of the following tertiary p-nitrobenzoate esters is

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q119: figure printed with the question
  1. (a) I < II < III < IV
  2. (b) I < IV < II < III
  3. (c) IV < I < III < II
  4. (d) II < I < IV < III

Answer and explanation with the VKC plan

Q120Medicinal chemistry / nitrogen mustards, aziridinium ions

Arrange the following three nitrogen mustards in decreasing order of reactivity towards their possible use as alkylating agents for clinical purpose :

UPSC Combined Geo-Scientist Prelims 2024 Paper II (Chemistry), Q120: figure printed with the question
  1. (a) I > III > II
  2. (b) II > I > III
  3. (c) III > I > II
  4. (d) II > III > I

Answer and explanation with the VKC plan

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